See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

g(x) = 2 2 2 x 1 x 1 x 2 2x x      taking x – 2 = t, the expression is 3 t 4 3 t t 4 3 t 2 t 7 t                    , again putting 3 2 t 7 p t          , expression changes to 1 1 p 2 2 p         where p  4 3 7    2 1 1 1 1 h p p 2 , h p 1 0 2 p 2 p                    minimum h(p) =   1 1 h 4 3 7 7 4 3 2 2 7 4 3             = 8