Total enthalpy change for freezing of 1 mol of water at 10ºC to ice at –10ºC is _____ (Given : fusH = x kJ/mol Cp[H2O(l)] = y J mol–1 K–1 Cp[H2O(s)] = z J mol–1 K–1 (A) – x – 10y – 10z (B) 10(100x + y

Question

Total enthalpy change for freezing of 1 mol of water at 10ºC to ice at –10ºC is _____ (Given : fusH = x kJ/mol Cp[H2O(l)] = y J mol–1 K–1 Cp[H2O(s)] = z J mol–1 K–1

(A) – x – 10y – 10z
(B) 10(100x + y + z)
(C) – 10(100x + y + z)
(D) x – 10y – 10z

Prashant Kotian · Accepted Answer

Correct answer: C. H2O(l) H2O(s) 10ºC nCP(l)T H2O(l) 0ºC H2O(s) 0ºC nCP(s)T 10ºC –Tfusion H = 1 × y(0 – 10) – x × 1000 + 1 × z(–10º – 0º) H = –10(100 ×+y + z) Joule

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