The number of paramagnetic metal complex species among [Co(NH3)63+], [Co(C2O4)3]3β, [MnCl6]3β, [Mn(C β JEE Mains Chemistry Past Papers Chemistry Question
Question
The number of paramagnetic metal complex species among [Co(NH3)63+], [Co(C2O4)3]3β, [MnCl6]3β, [Mn(CN)6]3β , [CoF6]3β and [FeF6]3β with same number of unpaired electrons is__________
π‘ Solution & Explanation
[Co(NH3)6]3+ Co3+ 3d6 ,2 ,2 g 2t , g e Diamagnetic (unpaired electron = 0) [Co(C2O4)3]3β Co3+ 3d6 ,2 ,2 g 2t , g e Diamagnetic (unpaired electron = 0) [MnCl6]3β Mn3+ 3d4 ,1 ,1 g 2t ,1 g e Paramagnetic (unpaired electron = 4) [Mn(CN)6]3β Mn3+ 3d4 ,1 ,2 g 2t , g e Paramagnetic (unpaired electron = 2) [CoF6]3β Co3+ 3d6 ,1 ,2 g 2t ,1 g e Paramagnetic (unpaired electron = 4) [Fe(CN)6]3β Fe3+ 3d5 ,2 ,2 g 2t , g e Paramagnetic (unpaired electron = 1) [FeF6]3β Fe3+ 3d5 ,1 ,1 g 2t ,1 g e Paramagnetic (unpaired electron = 5)