See image | AITS & Test Series — Chem-Mantra

AITS & Test SerieshardNUMERICAL

Question

See image

Answer: 579

💡 Solution & Explanation

Q = It 190.5 g Cu = 3 mole ½ mole Cu deposited by 1 F 3 mole Cu deposited = 6 F = 6  96500 = 579000 coulomb  x = 579000 Then x  10–3 = 579

💬

Still have doubts about this question?

Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry