There are five species P, Q, R, S and T. Spectroscopical analysis shows that P, Q and R are homonuclear diatomic species and have their bond order 2.5, 1.5 and 2.5 respectively and rest two species S

Question

There are five species P, Q, R, S and T. Spectroscopical analysis shows that P, 
Q and R are homonuclear diatomic species and have their bond order 2.5, 1.5 and 
2.5 respectively and rest two species S and T are heteronuclear diatomic species
and have bond order 3 and 2 respectively. All homonuclear diatomic species are 
paramagnetic and all heteronuclear diatomic species are diamagnetic in nature. 
P, R, S and T are monovalent positive ion and Q is monovalent negative ion :

Prashant Kotian · Accepted Answer

Correct answer: C. Step 1: Determine the geometry of ethyne (C2H2): each carbon is sp hybridized, yielding a symmetric linear structure (H-C≡C-H). Step 2: Analyze the structures of the options: H2O2 is open-book (non-planar), NO2 is bent (sp2 with an odd electron), SnCl2 is bent (sp2 with one lone pair). Step 3: Carbon dioxide (CO2) is sp hybridized and linear (O=C=O). Therefore, C2H2 is isostructural with CO2, matching option (d).

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