If one mole of a monoatomic gas (γ = 5/3) is mixed with one mole of a diatomic gas (γ = 7/5), the va — Thermodynamics and Thermochemistry Chemistry Question

💡 Solution & Explanation

For 1 mole of monoatomic gas: Cv1 = 1.5 R, Cp1 = 2.5 R. For 1 mole of diatomic gas: Cv2 = 2.5 R, Cp2 = 3.5 R. For the mixture: Cv_mix = (n1*Cv1 + n2*Cv2) / (n1+n2) = (1.5 R + 2.5 R)/2 = 2.0 R. Cp_mix = (n1*Cp1 + n2*Cp2) / (n1+n2) = (2.5 R + 3.5 R)/2 = 3.0 R. Thus, gamma_mix = Cp_mix / Cv_mix = 3.0 R / 2.0 R = 1.5.