Given: Hsub [C(graphite)] = 710 kJ mol–1 C–HH = 414 kJ mol–1 H–HH = 436 kJ mol–1 C=CH = 611kJ mol–1 The Hf for CH2=CH2 is ____________ kJ mol–1 (nearest integer | JEE Mains Chemistry Past Papers — Chem-Mantra | Chem-Mantra

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Given: Hsub [C(graphite)] = 710 kJ mol–1 C–HH = 414 kJ mol–1 H–HH = 436 kJ mol–1 C=CH = 611kJ mol–1 The Hf for CH2=CH2 is ____________ kJ mol–1 (nearest integer value)

Answer: .

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