The correct increasing order of stability of the complexes based on 0 value is : I. [Mn(CN)6]3– II. — JEE Mains Chemistry Past Papers Chemistry Question
Question
The correct increasing order of stability of the complexes based on 0 value is : I. [Mn(CN)6]3– II. [Co(CN)6]4– III. [Fe(CN)6]4– IV. [Fe(CN)6]3– (A) I < II < IV < III (B) III < II < IV < I (C) IV < III < II < I (D) II < III < I < IV
💡 Solution & Explanation
As C.F.S-E becomes more '–Ve' stability increases. [Mn(CN)6]3– [Co(CN)6]4– [Fe(CN)6]4– O.N. = +3 O.N. = +2 Fe = +2 Mn = 3d54s2 Co = 3d74s2 Fe(+2) = 3d6 Mn = (+3) = 3d4 Co (+2) = 3d7 , , g 2t eg0,0 1,1,2 g 2t eg0,0 , , g 2t 2eg1,0 C.F.S.E = –0.160. C.F.S.E = –1.80 C.F.S.E = –2.40 |Fe(CN)6|3– O.N = +3 Fe(+3) = 3d5 1, , g 2t eg0,0 C.F.S.E = –2.00 Hence (1) is correct.