Cu^2+(aq.) + X^-(aq.) -R.T.-> CuX↓ + X2. 'X' cannot be : — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Step 1: Identify starting materials: Copper(II) sulfate (CuSO4) and potassium iodide (KI) are both soluble salts. Step 2: Observe the redox reaction: Cu2+ oxidizes I- to iodine (I2), and is itself reduced to Cu+, which precipitates as white cuprous iodide (CuI↓). Step 3: Since a solid precipitate (CuI↓) is formed from soluble starting materials, this is classified as a precipitate formation reaction (type A).