For the reaction, 2H (g)+2NO(g) → N (g) + 2H O(g) The observed rate expression is, rate = k [NO] [H — Chemical Equilibrium Chemistry Question
Question
For the reaction, 2H (g)+2NO(g) → N (g) + 2H O(g) The observed rate expression is, rate = k [NO] [H ]. The rate expression for the reverse reaction is: 2 2 2 f 2 2 b 2 2 2 b 2 2 b 2 2 2 2 b 2 2 2 2 2 2 (A) k [N ][H O] (B) k [N ][H O] (C) k [N ][H O] /[H ] (D) k [N ][H O] /[NO]
Answer: C) K [N ][H O] /[H ]
💡 Solution & Explanation
The reverse reaction is: 2H (g) + 2NO(g) ⇌ N (g) + 2H O(g) The equilibrium constant, At equilibrium, rate of forward reaction=rate of backward reaction i.e. , Hence, rate of reverse reaction
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