See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let, the moles of KClO3 required to be ‘x’. Assuming 50% yield in each step. Moles of O2 formed in step (i) x 2  . Moles of each of K2MnO4 and Cl2 formed in (i) x 4  Moles of O2 formed in step (ii) = x 8 Total moles of O2 formed x x 5x 2 8 8   5x 60 8 32  x = 3