Consider the following reaction at 298 K. 2(g) 3(g) P 3 O O .K 2.47 10 . rG for the reaction is ____ — JEE Mains Chemistry Past Papers Chemistry Question
Question
Consider the following reaction at 298 K. 2(g) 3(g) P 3 O O .K 2.47 10 . rG for the reaction is _________ kJ. (Given R = 8.314 JK–1 mol–1)
Answer: .
💡 Solution & Explanation
2(g) 3(g) P 3 O O .K 2.47 10 . rG = – RT ln KP = – 8.314 × 10–3 × 298 × ln (2.47 × 10–29) = –8.314 × 10–3 × 298 × (–65.87) = 163.19 kJ
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