See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let the coordinates of P be   ,  Then PQ 2  and 2 2 OP   Since OPQ is an equilateral triangle OP = PQ  2 2 2 2 2 4 3   3   Also since   ,  lies on the given hyperbola, 2 2 2 2 1 a b     2 2 2 2 2 2 2 2 3 1 1 b 1 1 0 3 a b b a            .  2 2 1 4 2 e 1 e e 3 3 3       For More Material Join: @JEEAdvanced_2025 AITS-FT-I (Paper-2)-PCM(Sol.)-JEE(Advanced)/2025 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 9