See image β AITS & Test Series Chemistry Question
Question
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Answer: 00116.24
π‘ Solution & Explanation
οTf = Kf ο΄ m or, 0 - Tf = 1.86 1000 2 W ο΄ο΄ or, 0 β (-4.8) = 1.86 ο΄ 2000 W On solving, W = 775 g ο Mass of ice formed = 891.24 β 775 = 116.24 g
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