See image β AITS & Test Series Chemistry Question
Question
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Answer: C
π‘ Solution & Explanation
Due to double bond, the geometrical isomers are: 3 3 CH CH CH CH CH CH CH ο½ ο ο ο½ ο CH3 Cis Cis Trans Trans Cis Trans Trans Cis Identical When the double bonds are Cis and trans, the molecule becomes optically active. ο For trans Cis (two optical isomers are possible) ο Total no. of stereoisomers are: Geometrical(2) + Optical(2) = 4
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