See image — IUPAC and Nomenclature Chemistry Question

💡 Solution & Explanation

Step 1: Identify the parent chain. The molecule contains a carbonyl group (ketone) flanked by two carbon chains, each ending in a terminal alkene (vinyl group). Counting all carbons: CH2=CH-CH2-C(=O)-CH2-CH2-CH=CH2. That gives C1-C2-C3-C4(=O)-C5-C6-C7-C8, an 8-carbon chain. Parent chain name: octane → octa. Step 2: Identify the functional groups and their positions. There are two terminal double bonds and one ketone: - Double bond at C1-C2 (terminal alkene on left): position 1 - Double bond at C7-C8 (terminal alkene on right): position 7 - Ketone at C4: position 4 Step 3: Apply IUPAC nomenclature rules. The compound is an octa-diene with a ketone: - 'octa' = 8 carbons - '1,7-dien' = double bonds at positions 1 and 7 - '4-one' = ketone at position 4 Step 4: Combine to get the full IUPAC name: octa-1,7-dien-4-one. No alternative options are presented; the systematic name is uniquely determined by the structure. Therefore, the correct answer is octa-1,7-dien-4-one.