AITS & Test SerieshardNUMERICAL

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Answer: 12

💡 Solution & Explanation

Let a c 2b x    …(1) a b 2c y    ….(2) a b 3c z    ….(3) c z y;b x z 2y      a x 5y 3z       4 x z 2y 8 z y 2y x x y z            y 2x z 2y 17 2 4 x y y z                  17 4 2 8 2    12 2 17   For More Material Join: @JEEAdvanced_2025 AITS-FT-I (Paper-2)-PCM(Sol.)-JEE(Advanced)/2025 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 12

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