Compound A, C5H10O5, given a tetraacetate with AC2O and oxidation of A with Br2–H2O gives an acid, C5H10O6. Reduction of A with HI gives isopentane. The possible structure of A is :

Question

Prashant Kotian · Accepted Answer

Correct answer: C. COOH CH2–C–OH OH CH2OH H–C–OH      O H / Br 2 CHO CH2–C–OH OH CH2OH H–C–OH HI Iso-pentane      O Ac . 2 CHO CH2–C–OAc OAc CH2OAc H–C–OAc

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