The oxidation states of transition metal atoms in K2Cr2O7, KMnO4 and K2FeO4, respectively, are x, y — JEE Mains Chemistry Past Papers Chemistry Question
Question
The oxidation states of transition metal atoms in K2Cr2O7, KMnO4 and K2FeO4, respectively, are x, y and z. The sum of x, y and z is_______.
Answer: .
💡 Solution & Explanation
Compound Oxidation state of transition element. (i) K2Cr2O7 x = +6 (ii) KMnO4 y = +7 (iii) K2FeO4 z = +6 so (x + y + z) = 19
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