See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

g(x) = 4 – 2x, 0  x  2, f(x) = 4x – x2 required area       3 5 1 2 2 2 3 5 4x x dx 4 2x dx 2 2 1           17 10 5 4 2 3    . (1,2)     3 5,2 5 1   (2 2, 2) 