A gaseous mixture of three gases A, B and C has a pressure of 10 atm. The total number of moles of all the gases is 10. If the partial pressures of A and B are 3.0 and 1.0 atm, respectively, and if C

Question

A gaseous mixture of three gases A, B and C has a pressure of 10 atm. The total number of moles of all the gases is 10. If the partial pressures of A and B are 3.0 and 1.0 atm, respectively, and if C has molecular mass of 2.0, what is the mass of C, in g, present in the mixture?

Prashant Kotian · Accepted Answer

Correct answer: C. p_total = p_a + p_b + p_c → 10 = 3 + 1 + p_c → p_c = 6 atm. mole fraction of c is y_c = p_c/p_total = 6/10 = 0.6. moles of c = y_c × n_total = 0.6 × 10 = 6 mol. mass of c = 6 mol × 2 g/mol = 12 g.

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