See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

(for Q.33 and 34) A (l)  A (s)  H = – 500 J/Mole H = U + (PV) H = U + P (V) = U + 1 × 100 (-2050) /1000 U = – 400 J/Mole |U| = 400 Ans.