The structure of B3N3H6 is as follows : [SEE DIAGRAM] How may derivative structures of B3N3H4X2 can — Chemical Bonding Chemistry Question
Question
The structure of B3N3H6 is as follows : [SEE DIAGRAM] How may derivative structures of B3N3H4X2 can be derived from the basic structure, by the replacement of two hydrogen atoms?
![Chemistry diagram for: The structure of B3N3H6 is as follows : [SEE DIAGRAM] How may derivative structures of B3N3H4X2 can be derived from the](/_next/image?url=https%3A%2F%2Furywdhpqdpvmqzlenttu.supabase.co%2Fstorage%2Fv1%2Fobject%2Fpublic%2Fquestion-images%2Fvkj%2Fch03_Q076.png&w=1920&q=75)
💡 Solution & Explanation
Step 1: Determine the positions of the atoms in the hexagonal borazine ring, which alternates Boron and Nitrogen atoms: B(1)-N(2)-B(3)-N(4)-B(5)-N(6). Step 2: Identify the possible structural isomers for a disubstituted borazine (B3N3H4X2) where two hydrogens are replaced by X: 1. ortho-isomer: substituents on adjacent B and N atoms (1,2-position). 2. meta-B-isomer: substituents on two meta-positioned Boron atoms (1,3-position). 3. meta-N-isomer: substituents on two meta-positioned Nitrogen atoms (2,4-position). 4. para-isomer: substituents on opposite B and N atoms (1,4-position). Step 3: This yields exactly 4 structurally distinct isomers. Therefore, option (c) is correct.