At 298K N2(g) + 3H2(g) 2NH3(g)K1 = 4 105 N2(g) + O2(g) 2NO(g) K2 = 1.6 1012 H2(g) + 1 O2(g) H2O(g),K — JEE Mains Chemistry Past Papers Chemistry Question
Question
At 298K N2(g) + 3H2(g) 2NH3(g)K1 = 4 105 N2(g) + O2(g) 2NO(g) K2 = 1.6 1012 H2(g) + 1 O2(g) H2O(g),K3 = 1.0 10–13 Based on above equilibria, the equilibrium constant of the reaction, 2NH3(g) + 5 O2 (g) 2NO (g) + 3H2O (g) is ____________10–33 (Nearest integer).
Answer: .
💡 Solution & Explanation
Target equation = eq(2) –eq(1) + 3eq(3) K = 3 2 K ) K ( K = ) 4 ( ) 1 ( 6 . 5 13 – = ) 4 ( 10 5 – = 4 × 10–33 Ans. = 4
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