Consider the following transformation :<br>2CuX2 2CuX + X2<br>Then X^- can be : — d and f Block Elements Chemistry Question

💡 Solution & Explanation

Step 1: Divalent copper (Cu2+) is a moderately strong oxidizing agent. Step 2: CN- and I- are very strong reducing agents and cannot coexist with Cu2+ in solution. Instead, they undergo an immediate redox reaction at room temperature to form Cu(I) halides/cyanides and release free iodine (I2) or cyanogen ((CN)2) gas. Step 3: Therefore, CuI2 and Cu(CN)2 do not exist and decompose spontaneously into CuI/CuCN and I2/(CN)2. Thus, X- can be CN- or I-, corresponding to option (c).