KClO3 6FeSO4 + 3H2SO4 KCl + 3Fe2(SO4)3 ± 3H2O The above reaction was studied at 300 K by monitoring — JEE Mains Chemistry Past Papers Chemistry Question
Question
KClO3 6FeSO4 + 3H2SO4 KCl + 3Fe2(SO4)3 ± 3H2O The above reaction was studied at 300 K by monitoring the concentration of FeSO4 in which initial concentration was 10 M and after half an hour became 8.8 M. The rate of production of Fe2(SO4)3 is _______ × 10–6 mol L–1 s–1. (Nearest integer)
Answer: .
💡 Solution & Explanation
KClO3 + 6FeSO4 + 3H2 KCl + 3Fe2(SO4)3 + 3H2O Initial conc. of FeSO4 = 10 M after 1 hr. = 8.8 rate of consumption of FeSO4 – dt d [FeSO4] sec 30 . = 0.000667 m/sec dt ] FeSO [d = dt ] ) SO ( Fe [d 4 rate of production of Fe2(SO4)3 = 0.000333 M sec–1.
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