A sample of gas at 35°C and 1 atmospheric pressure occupies a volume of 3.75 l. At what temperature should the gas be kept, if it is required to reduce the volume to 3.0 l at the same pressure?

Question

Prashant Kotian · Accepted Answer

Correct answer: A. According to Charles's law: V1 / T1 = V2 / T2. Given: V1 = 3.75 l, T1 = 35 + 273 = 308 K, V2 = 3.0 l. T2 = (V2 * T1) / V1 = (3.0 * 308) / 3.75 = 246.4 K. Converting to Celsius: t2 = 246.4 - 273 = -26.6°C.

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