The rate law for the reaction: RCl + (aq) → ROH + is given by, rate = K1[RCl]. The rate of the reaction will be
1. Doubled on doubling the concentration of
2. Halved on reducing the concentrati

Question

The rate law for the reaction: RCl + $NaOH$(aq) → ROH + $NaCl$ is given by, rate = K1[RCl]. The rate of the reaction will be
1. Doubled on doubling the concentration of $NaOH$
2. Halved on reducing the concentration of alkyl halide to one half
3. Increased on increasing the temperature of the reaction
4. Unaffected by increasing the temperature of the reaction

Prashant Kotian · Accepted Answer

Correct answer: D. Rate is independent of []. Halving [RCl] halves the rate. Rate increases with temperature because K increases. Statements 2 and 3 are correct.

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