See image — AITS & Test Series Chemistry Question
Question
See image

Answer: A,B,C,D
💡 Solution & Explanation
In linear molecule 3 translation + 2 Rotation = 5 motion Energy contribution 1 5 5 KT KT 2 2 by one molecule av 5 5 N KT RT 2 2 by one mole. In bent triatomic 3 translation + 3 Rotation = 6 motion Energy contribution 1 6 KT 2 = 3 KT by one molecule By one mole = 3 KT × Nav = 3RT In monoatomic 3 translation motion Energy contribution 3 RT 2 by one molecule.
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