See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

Let E be mid-point of AB 3x2 – 8x – 16 = 0 1 2 8 x x 3   1 2 x x 4 2 3    x-coordinate of E is 4 / 3 So SP = 2SE  SE = 8/3 and SP = 16 / 3