Correct answer: B. R f R 2f 2    f sin 30 2f   ( is not small) PF = R R sec 2   PF = 1 2f 1 3        SECTION – B

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AITS & Test SerieshardMCQ SINGLE

Question

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Answer: B

💡 Solution & Explanation

R f R 2f 2    f sin 30 2f   ( is not small) PF = R R sec 2   PF = 1 2f 1 3        SECTION – B

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