AITS & Test SerieshardNUMERICAL

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Question

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Answer: 4

💡 Solution & Explanation

Sol. 0 ( ) 2 i b d x a dx x h                 0 1 2 a h i a b a d dx h x                     0 [ ln ] 2 a h a i b h a x h       0 ln 2 i b a n h a h a                   0 ln2 2 i b h a a h        M i    0 ln2 2 b M h a h         4  7 10 2    2  1 ln2       Ans.: 8 4 10 [1 ln2]     y b x h a dx SECTION – D

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