Molar conductivity of a weak acid HQ of concentration 0.18 M was found to be 1/30 of the molar conductivity of another weak acid HZ with concentration of 0.02 of M. If Q happened to be equal with Z ,

Question

Molar conductivity of a weak acid HQ of concentration 0.18 M was found to be 1/30 of the molar conductivity of another weak acid HZ with concentration of 0.02 of M. If Q happened to be equal with Z , then the difference of the pKa values of the two weak acids (pKa(HQ)–pKa(HZ)) is _______ (Nearest integer). [Given : degree of dissociation () << 1 for both weak acids, ° : limiting molar conductivity of ions]

Prashant Kotian · Accepted Answer

Correct answer: .. Ka(HQ) = C11 m m (HQ) (HQ)     Ka(HZ) = C22 m m (HZ) (HZ)     a 1 a 2 K (HQ) C . K (HZ) C          m m (HQ) 0.18. 0.02 (HZ)          a a K (HQ) 1 K (HQ) 100          pKa(HQ) – pKa(HZ) = 2

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