Thermodynamics and ThermochemistryhardMCQ SINGLE

At 25°C and 1 atm pressure, the enthalpy of combustion of benzene (l) and acetylene (g) are –3268 kJThermodynamics and Thermochemistry Chemistry Question

Question

At 25°C and 1 atm pressure, the enthalpy of combustion of benzene (l) and acetylene (g) are –3268 kJ mol and –1300 kJ mol , respectively. The change in enthalpy for the reaction 3C H (g) → C H (l), is –1 –1 2 2 6 6 –1 –1 –1 –1 6 6 2 2 2 1 2 2 2 2 2 2 2 2 2 6 3 3 2 1 –1 (A) +324 kJ mol (B) +632 kJ mol (C) –632 kJ mol (D) –732 kJ mol

Answer: C) –632 KJ MOL

💡 Solution & Explanation

C H + O → 6CO + 3H O… ∆H ……Rxn (1) C H + O → 2CO + H O… ∆H ……..Rxn (2) ---------------- 3C H → C H … ∆H ………Rxn (3) (3) = 3 × (2) – (1) ∴ ∆H = 3(∆H ) – ∆H = 3 × (–1300) – (–3268) = –3900 + 3268 = –632 kJ mol

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Advanced Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry