Light green (Compound 'A') White Residue (B) C + D + E (i) 'D' and 'E' are two acidic gas. (ii) 'D' is passed through HgCl2 solution to give yellow ppt. (iii) 'E' is passed through water first and the

Question

Light green (Compound 'A') $\xrightarrow{\Delta}$ White Residue (B) 
$\xrightarrow{	ext{High Temp.}}$ C + D + E
(i) 'D' and 'E' are two acidic gas.
(ii) 'D' is passed through HgCl2 solution to give yellow ppt.
(iii) 'E' is passed through water first and then H2S is passed, white turbidity 
is obtained.
(iv) A is water soluble and addition of HgCl2 in it, yellow ppt is obtained but 
white ppt does not turn into grey on addition of excess solution of 'A'. [1]

Prashant Kotian · Accepted Answer

Correct answer: D. Step 1: When silver halides are fused with sodium carbonate, they undergo a displacement reaction that initially produces silver carbonate. Step 2: At the high temperatures of fusion, silver carbonate is highly unstable and decomposes to silver oxide, which further decomposes to metallic silver (Ag) and oxygen. Step 3: The overall reaction is: 4AgCl + 2Na2CO3 ---> 4NaCl + 2CO2 + O2 + 4Ag. Hence, metallic silver (Ag) is formed, matching option (c).

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