See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

(A) 3s 3p 3d st 1 excitation Cl : So, x 5  (B) 1s   y 3  nd 2 excitation He : 2s st 1 excitation (C) 1s 2p nd 2 excitation H: 2s st 1 excitation degenarate 3s 3p 3d So, z = 9 SECTION – C