Dissociation of a gas A2 takes place according to the following chemical reactions. At equilibrium, — JEE Mains Chemistry Past Papers Chemistry Question
Question
Dissociation of a gas A2 takes place according to the following chemical reactions. At equilibrium, the total pressure is 1 bar at 300K. A (g) 2A(g) The standard Gibbs energy of formation of the involved substances has been provided below: º t Substance G / kJmol A 100.00 A 50.832 The degree of dissociation of A2(g) is given by (x × 10 –2) 1/2 where x = _________. (Nearest integer). [Given : R = 8 J mol –1 K –1, log 2 = 0.3010, log 3 = 0.48]
Answer: .
💡 Solution & Explanation
–1.664 × 10 3 = –8.3 × 300 lnKP lnKP = 0.693 KP = 2 0 4 P 1 3 1/2 100 10 = (33.33 × 10 –2) 1/2 ALLEN
💬Ask on WhatsApp →
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes