JEE Mains Chemistry Past PapershardNUMERICAL

Dissociation of a gas A2 takes place according to the following chemical reactions. At equilibrium, JEE Mains Chemistry Past Papers Chemistry Question

Question

Dissociation of a gas A2 takes place according to the following chemical reactions. At equilibrium, the total pressure is 1 bar at 300K. A (g) 2A(g) The standard Gibbs energy of formation of the involved substances has been provided below: º t Substance G / kJmol A 100.00 A 50.832 The degree of dissociation of A2(g) is given by (x × 10 –2) 1/2 where x = _________. (Nearest integer). [Given : R = 8 J mol –1 K –1, log 2 = 0.3010, log 3 = 0.48]

Answer: .

💡 Solution & Explanation

–1.664 × 10 3 = –8.3 × 300 lnKP lnKP = 0.693 KP = 2 0 4 P 1    3  1/2 100 10          = (33.33 × 10 –2) 1/2 ALLEN

💬
Still have doubts about this question?
Send it to our AI chemistry tutor on WhatsApp — gets answered in minutes
Ask on WhatsApp →

Practice 22,000+ questions like this

AI-adaptive practice, video lectures, and full JEE Mains Chemistry content — all in one place.

JEE Advanced · JEE Mains · NEET · IChO · AP Chemistry