The rate law for a reaction between the substances A and B is given by rate = K [A]^n [B]^m. On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the ear

Question

The rate law for a reaction between the substances A and B is given by rate = K [A]^n [B]^m. On doubling the concentration of A and halving the concentration of B, the ratio of the new rate to the earlier rate of the reaction will be as

Prashant Kotian · Accepted Answer

Correct answer: D. rate_new / rate_old = (2[A])^n * ([B]/2)^m / ([A]^n [B]^m) = 2^n * (1/2)^m = 2^(n-m).

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