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AITS & Test SerieshardNUMERICAL

Question

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Answer: 00021.00

💡 Solution & Explanation

isotpic field Ligand field 0 0 0 0 E =PE E =6 (-0.4 )+3 PE CFSE= 2 PE + 6 (-0.4 ) -8800=2 20800 - 2.4 21000

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