See image | AITS & Test Series — Chem-Mantra

Name: JEE Advanced Chemistry
Price: 7999 INR
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Question

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Answer: 5

💡 Solution & Explanation

2 2 4 RH Ca RCa 2H 3 10 M        So, 2 4 3 Ca 10 M 2        So, mass of 3 CaCO present in 1 L hard water 4 2 3 10 100

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