See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

In the undistorted unit cell, X+ = 4 ions Y- = 4 ions Ions present on the horizontal plane 4-face centre = 2Y- 4-edge centre = 1X+ 1-body centre = 1X+  Ions left in the distorted unit cell is: For More Join: @FIITJEE_AITS_for_JEE AITS-CRT-IV (Paper-2)-PCM(Sol.)-JEE(Advanced)/2025 FIITJEE Ltd., FIITJEE House, 29-A, Kalu Sarai, Sarvapriya Vihar, New Delhi -110016, Ph 46106000, 26569493, Fax 26513942 website: www.fiitjee.com 6 X+ = 4 – 2 = 2 Y- = 4 – 2 = 2  The required formula of the solid is X2Y2 or XY.