See image — AITS & Test Series Chemistry Question

💡 Solution & Explanation

(I)   2 5 C H ONa E 2    Br (II) N 3 S 2 CH I    ONa NaI  O CH3 (III)     KOH alc. E1cb   O Br O 2 KBr H O   (IV)     2 KOH alc. E     N(CH3)3 3 2 NMe H O   Section – B