The amount of energy released when an electron jumps from the seventh excited state to the first exc — Atomic Structure Chemistry Question

💡 Solution & Explanation

The seventh excited state corresponds to n_2 = 8, and the first excited state corresponds to n_1 = 2. For He^+ (Z = 2), the transition energy is given by: Δ E = 13.6 * Z^2 * (1/n_1^2 - 1/n_2^2) = 13.6 * 4 * (1/2^2 - 1/8^2) = 13.6 * 4 * (1/4 - 1/64) = 13.6 * 4 * (15/64) = 13.6 * (15/16) = 12.75 eV.