HgI2↓ + KI -> K2[HgI4] — Redox Reactions and Volumetric Analysis Chemistry Question

💡 Solution & Explanation

Step 1: Identify starting materials: Mercuric iodide (HgI2↓) is a brilliant scarlet-red insoluble precipitate. Step 2: Analyze the reaction with excess potassium iodide (KI): Iodide ions coordinate with Hg2+ to form the highly stable, soluble complex potassium tetraiodomercurate(II) (K2[HgI4]). Step 3: Since the red precipitate is dissolved to yield a clear soluble complex solution, this is a precipitate dissolution reaction (type B).