The wavelength of photon ‘A’ is 400 nm. The frequency of photon ‘B’ is 10 16s –1. The wave number of photon ‘C’ is 10 4 cm –1. The correct order of energy of these photons is : (A) C B A (B) B A

Question

The wavelength of photon ‘A’ is 400 nm. The frequency of photon ‘B’ is 10 16s –1. The wave number of photon ‘C’ is 10 4 cm –1. The correct order of energy of these photons is :

(A) C > B > A
(B) B > A > C
(C) A > B > C
(D) A > C > B

Prashant Kotian · Accepted Answer

Correct answer: B. (1) Wavelength of A = 400 nm. (2) Wavelength of B () = C = 16 3 10  = 3 × 10 –8 = 30 × 10 –9 = 30 nm. (3) Wavelength of C() = 1 10   = 10 –4 cm = 10 –6 m = 1000 nm Here C > A > B Energy(E)  So EB > EA > EC Ans. (2) is correct.

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