Metal + dil. HCl A B (white ppt.) A C Metal (M) β s Block Elements Chemistry Question
Question
Metal + dil. HCl $\rightarrow$ A $\xrightarrow{\text{Na}_2\text{HPO}_4 / \text{NH}_4\text{OH}}$ B (white ppt.) A $\xrightarrow{\text{HCl(g), Heated}}$ C $\xrightarrow{\text{Electrolysis in presence of NaCl}}$ Metal (M)
π‘ Solution & Explanation
Step 1: Down the group of alkali metals (Group 1), the nuclear charge increases, but the number of electron shells also increases. Step 2: The addition of new electron shells causes the valence electrons to be located further from the nucleus, which leads to a decrease in first ionization energy, electronegativity, and the hydration energy of the univalent cations. Step 3: Conversely, the atomic and ionic radii systematically increase down the group. Therefore, atomic radius increases with increasing atomic number, matching option (d).