1.22 g of an organic acid is separately dis — JEE Mains Chemistry Past Papers Chemistry Question

💡 Solution & Explanation

ution in benzene in ºC is x × 10–2. The value of x is________ (Nearest integer) [Atomic mass: C = 12.0, H =1.0, 0 = 16.0] ,d dkcZfud vEy 1.22 g dks 100 g csUthu (Kb = 2.6 K kg mol–1) rFkk 100 g ,slhVksu (Kb=1.7 K kg mol–1) esa vyx vyx ?kksyk x;k gSA vEy dk csUthu esa f}r;u Kkr gS] ijUrq ,slhVksu esa ;g ,dyd jgrk gSA ,s;hVksu esa cus foy;u dk DoaFkukad 0.17ºC c<+ tkrk gSA csUthu esa cus foy;u ds DoFkukad esa c<+r ºC esa x × 10–2 gSA x dk eku gS ________ (fudVre iw.kkZd esa) [ijekf.od lagfr: C = 12.0, H =1.0, 0 = 16.0] Ans. (13) Sol. Tb = i × kb × molality ; m = 1 w GMM w  For Acetone solution 0.17 = 1 × 1.7 × GMM . × 1000 | JEE MAIN-2021 | DATE : 31-08-2021 (SHIFT-2) | PAPER-1 | OFFICAL PAPER | CHEMISTRY PAGE # 12 GMM of substance = 122 gm/mol For Benzene solution Tb = i × kb × m = 1 × 2