The smallest Cs-to-Cl inter-nuclear distance in the crystal is — Solid State Chemistry Question

💡 Solution & Explanation

The Cs+ ion and Cl- ion touch along the body diagonal of the cube. The shortest Cs-to-Cl distance is half the body diagonal: d = a * sqrt(3) / 2 = 4.3 * 1.732 / 2 = 3.72 A.