JEE Mains Chemistry Past PapershardNUMERICAL

The mass of gas adsorbed, x, per unit mass of adsorbate, m, was measured at various pressures, p. A JEE Mains Chemistry Past Papers Chemistry Question

Question

The mass of gas adsorbed, x, per unit mass of adsorbate, m, was measured at various pressures, p. A graph between log m x and log p gives a straight line with slope equal to 2 and the intercept equal to 0.4771. The value of m x at a pressure of 4 atm is : (Given log 3 = 0.4771)

Answer: .

💡 Solution & Explanation

.       m x = n ) P ( k       m x log = logk + P log n  Slope = n = 2 So n = . Intercept  logk = 0.477 So k = Antilog (0.477) = 3 So n ) P ( k m x        = 3[4]2 = 48 logP logk=0.477 Slope=2       m x log

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