When 0.18 g of glucose was burnt in a bomb calorimeter, the temperature rose by 4 K. The heat capacity of the calorimeter system is (delta_c H° = -2.8 × 10^6 J/mol glucose)

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Prashant Kotian · Accepted Answer

Correct answer: A. Molar mass of glucose (C6H12O6) = 180 g/mol. Moles of glucose burnt: n = 0.18 g / 180 g/mol = 10^-3 mol. Total heat released during combustion: q = n *

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